ENERGY/WORK/POWER
Energy: The ability to do work, makes matter/object move.
Work: A force exerted on an object that causes it to move.
Power: The rate at which work is done on an object.
Work: A force exerted on an object that causes it to move.
Power: The rate at which work is done on an object.
Energy
The amount of energy needed to create a smash in badminton is very high. When the shuttlecock is hit back into the air it has gravitational potential energy. The main types of used energy in badminton are kinetic every and heat energy. When the shuttlecock is hit by the racket, it has gravitational potential energy. In this example, we will determine the kinetic energy in a shuttlecock (5g) smashed at 16m/s and the gravitational potential energy of the shuttlecock. The height of the shuttlecock is at 3.7m.
Ek is the kinetic energy(J), m is the mass of the object(kg), and v is the speed of the object(m/s).
Kinetic Energy Formula: Ek = (1/2)mv^2
Ek = ?
m = 0.005kg
v = 16m/s
Ek = (1/2)(0.005)(16^2)
Ek = (1/2)(0.005)(256)
Ek = 0.64J
∴ The kinetic energy in the shuttlecock is 0.64J.
ΔEg is the change in energy from the ground to the raised height, m is the mass of the object, g is the acceleration of gravity, and Δh is the change in height.
Gravitation Potential Energy Formula: ΔEg = mgΔh
ΔEg = (0.005)(9.8)(3.7)
ΔEg = 0.01813J
∴The shuttlecock has potential energy of 0.01813J.
Ek is the kinetic energy(J), m is the mass of the object(kg), and v is the speed of the object(m/s).
Kinetic Energy Formula: Ek = (1/2)mv^2
Ek = ?
m = 0.005kg
v = 16m/s
Ek = (1/2)(0.005)(16^2)
Ek = (1/2)(0.005)(256)
Ek = 0.64J
∴ The kinetic energy in the shuttlecock is 0.64J.
ΔEg is the change in energy from the ground to the raised height, m is the mass of the object, g is the acceleration of gravity, and Δh is the change in height.
Gravitation Potential Energy Formula: ΔEg = mgΔh
ΔEg = (0.005)(9.8)(3.7)
ΔEg = 0.01813J
∴The shuttlecock has potential energy of 0.01813J.
Work
Work is when a force is applied to an object which then travels a distance. In this example we will determine how much work is done on a shuttlecock by a badminton player when he/she applies a force of 370N on a shuttlecock that travels a total distance of 9m.
W represents the work done(J), Fapp is the applied force(N), and Δd is the distance(m).
Formula for Work: W = Fapp x Δd
W = ?
Fapp = 370N
Δd = 9m
W = (370)(9)
W = 3330J
The amount of work that the badminton player has done to the shuttlecock for it to travel 9m is 3330J
W represents the work done(J), Fapp is the applied force(N), and Δd is the distance(m).
Formula for Work: W = Fapp x Δd
W = ?
Fapp = 370N
Δd = 9m
W = (370)(9)
W = 3330J
The amount of work that the badminton player has done to the shuttlecock for it to travel 9m is 3330J
Power
Continuing on from the variables and examples used in work, we will determine how much power was needed from that badminton player to hit that shuttlecock over a distance of 9m. The time taken for the shuttlecock to travel that 9m was 0.9 seconds.
P represents the power(watts), W is the work(joules), and t is the time taken(s)
Formula for Power: P = W/t
P = ?
W = 3330J
t = 0.9s
W = 3330/0.9
W = 3700w
The amount of power that the badminton used to hit that shuttlecock was 3700w
P represents the power(watts), W is the work(joules), and t is the time taken(s)
Formula for Power: P = W/t
P = ?
W = 3330J
t = 0.9s
W = 3330/0.9
W = 3700w
The amount of power that the badminton used to hit that shuttlecock was 3700w